(x-5)(4x^2-4x+101)=0

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Solution for (x-5)(4x^2-4x+101)=0 equation: 


Simplifying
(x + -5)(4x2 + -4x + 101) = 0

Reorder the terms:
(-5 + x)(4x2 + -4x + 101) = 0

Reorder the terms:
(-5 + x)(101 + -4x + 4x2) = 0

Multiply (-5 + x) * (101 + -4x + 4x2)
(-5(101 + -4x + 4x2) + x(101 + -4x + 4x2)) = 0
((101 * -5 + -4x * -5 + 4x2 * -5) + x(101 + -4x + 4x2)) = 0
((-505 + 20x + -20x2) + x(101 + -4x + 4x2)) = 0
(-505 + 20x + -20x2 + (101 * x + -4x * x + 4x2 * x)) = 0
(-505 + 20x + -20x2 + (101x + -4x2 + 4x3)) = 0

Reorder the terms:
(-505 + 20x + 101x + -20x2 + -4x2 + 4x3) = 0

Combine like terms: 20x + 101x = 121x
(-505 + 121x + -20x2 + -4x2 + 4x3) = 0

Combine like terms: -20x2 + -4x2 = -24x2
(-505 + 121x + -24x2 + 4x3) = 0

Solving
-505 + 121x + -24x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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